**Why is a "normal" tangent graph uphill, but a "normal" cotangent graph downhill?**

**Basically, a normal tangent graph is uphill because it is based on its asymptotes. They are located at pi/2 and 3pi/2. Furthermore, the quadrants are shown as positive, negative, positive, and negative (based on sin/cos). Cotangent is downhill because its asymptotes are located at 0 and pi. Because of where the asymptotes are located, it is downhill. The quadrants are positive, negative, positive, negative. The asymptotes are where sine and cosine are equal to 0 (making the ratio undefined).**

Visual of Tangent

(https://www.desmos.com/calculator) As you can see, the colors represent the different quadrants (I,II,III,IV)
Asymptotes at pi over 2 and 3pi over 2 |

Visual of Cotangent

(https://www.desmos.com/calculator) |

http://www.oocities.org/mathnuts/TrigAGModule1-TrigFunctions/graphs-general-tan-cot-sec-csc-sec6p8/graphs-general-tan-cot-sec-csc.htm Asymptotes at 0 radians and pi |

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